What is the asymptotes of f(x)=2sec(pi/4 (x+1)) ?

The asymptotes of f(x)=2sec(pi/4 (x+1)) is Vertical: x=1+8n,x=5+8n

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asymptotes of f(x)=2sec(pi/4 (x+1))

asymptotes

f (x) = 2 sec (\frac{π}{4} (x + 1))

Vertical : x = 1 + 8 n, x = 5 + 8 n

Solution steps

Vertical asymptotes of

2 sec (\frac{π}{4} (x + 1)) : x = 1 + 8 n, x = 5 + 8 n

Horizontal Asymptotes of

2 sec (\frac{π}{4} (x + 1)) :

None

Slant Asymptotes of

2 sec (\frac{π}{4} (x + 1)) :

None

Vertical : x = 1 + 8 n, x = 5 + 8 n

f (x) = \frac{( 5 + 2 ^{x} )}{1 - 2 ^{x}}

f (x) = \frac{4 x + 2}{x + 2}

(x^{2} + 10) (9 - x^{2})

f (x) = \frac{x}{3 + 2 ln ( x )}

\frac{8 x ^{4}}{x ^{4} + 2}

What is the asymptotes of f(x)=2sec(pi/4 (x+1)) ?
The asymptotes of f(x)=2sec(pi/4 (x+1)) is Vertical: x=1+8n,x=5+8n