What is the domain of f(x)=sqrt(x^2-4)+1 ?

The domain of f(x)=sqrt(x^2-4)+1 is x = 2

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domain of f(x)=sqrt(x^2-4)+1

domain

f (x) = x^{2} - 4 + 1

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

f (x) = - 2 x^{2} - 4 x + 14

\frac{x ^{2} - 9}{x ^{2}}

sin (3 x)

f (x) = \frac{2 x + 5}{x - 1}

f (x) = \frac{x ^{2} + 5 x + 5}{x + 1}

What is the domain of f(x)=sqrt(x^2-4)+1 ?
The domain of f(x)=sqrt(x^2-4)+1 is x<=-2\lor x>= 2