What is the asymptotes of f(x)=(x^2+e^x)/(x+1) ?

The asymptotes of f(x)=(x^2+e^x)/(x+1) is Vertical: x=-1

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asymptotes of f(x)=(x^2+e^x)/(x+1)

asymptotes

f (x) = \frac{x ^{2} + e ^{x}}{x + 1}

Vertical : x = - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + e ^{x}}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + e ^{x}}{x + 1} :

None

Vertical : x = - 1

f (x) = \frac{x ^{3} + x ^{2} + 3}{x ^{2} + 4}

f (x) = \frac{x ^{3} - 2 x ^{2}}{x ^{2} - 4}

f (x) = \frac{e ^{x}}{1 + e ^{x}}

f (x) = \frac{4 x ^{2} - 4}{2 x - 2}

f (x) = 2 x^{\frac{5}{3}} - 5 x^{\frac{4}{3}}

What is the asymptotes of f(x)=(x^2+e^x)/(x+1) ?
The asymptotes of f(x)=(x^2+e^x)/(x+1) is Vertical: x=-1