What is the asymptotes of f(x)=(x^2+2x-8)/(x^2-4) ?

The asymptotes of f(x)=(x^2+2x-8)/(x^2-4) is Vertical: x=-2,Horizontal: y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2+2x-8)/(x^2-4)

asymptotes

f (x) = \frac{x ^{2} + 2 x - 8}{x ^{2} - 4}

Vertical : x = - 2, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x - 8}{x ^{2} - 4} : x = - 2

Horizontal Asymptotes of

\frac{x ^{2} + 2 x - 8}{x ^{2} - 4} : y = 1

Slant Asymptotes of

\frac{x ^{2} + 2 x - 8}{x ^{2} - 4} :

None

Vertical : x = - 2, Horizontal : y = 1

x + 1

f (x) = \frac{5 x}{x + 2}

f (x) = \frac{2 x + 7}{- 3 x - 1}

4 x^{2}

f (x) = \frac{x ^{3} - x - 4}{- x ^{2} + 5 x - 4}

What is the asymptotes of f(x)=(x^2+2x-8)/(x^2-4) ?
The asymptotes of f(x)=(x^2+2x-8)/(x^2-4) is Vertical: x=-2,Horizontal: y=1