What is the asymptotes of f(x)=log_{3}(x+1) ?

The asymptotes of f(x)=log_{3}(x+1) is Vertical: x=-1

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asymptotes of f(x)=log_{3}(x+1)

asymptotes

f (x) = lo g_{3} (x + 1)

Vertical : x = - 1

Solution steps

Vertical asymptotes of

lo g_{3} (x + 1) : x = - 1

Horizontal Asymptotes of

lo g_{3} (x + 1) :

None

Slant Asymptotes of

lo g_{3} (x + 1) :

None

Vertical : x = - 1

f (x) = lo g_{4} (x + 2)

f (x) = \frac{4 x ^{2} + 2 x - 7}{2 x + 3}

- 3^{x}

f (x) = \frac{x - 1}{x ^{2} + x - 2}

f (x) = \frac{4 x}{2 x ^{2} + 1}

What is the asymptotes of f(x)=log_{3}(x+1) ?
The asymptotes of f(x)=log_{3}(x+1) is Vertical: x=-1