What is the asymptotes of f(x)=(x^2+2x+1)/(7x^2-x-8) ?

The asymptotes of f(x)=(x^2+2x+1)/(7x^2-x-8) is Vertical: x= 8/7 ,Horizontal: y= 1/7

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asymptotes of f(x)=(x^2+2x+1)/(7x^2-x-8)

asymptotes

f (x) = \frac{x ^{2} + 2 x + 1}{7 x ^{2} - x - 8}

Vertical : x = \frac{8}{7}, Horizontal : y = \frac{1}{7}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x + 1}{7 x ^{2} - x - 8} : x = \frac{8}{7}

Horizontal Asymptotes of

\frac{x ^{2} + 2 x + 1}{7 x ^{2} - x - 8} : y = \frac{1}{7}

Slant Asymptotes of

\frac{x ^{2} + 2 x + 1}{7 x ^{2} - x - 8} :

None

Vertical : x = \frac{8}{7}, Horizontal : y = \frac{1}{7}

f (x) = \frac{6 x + 1}{6 + 3 x}

f (x) = tan (x + \frac{π}{3})

sin (x) - x

\frac{x ^{2} - 3 x - 4}{x + 2}

\frac{x ^{2} - x}{x ^{2} - 1}

What is the asymptotes of f(x)=(x^2+2x+1)/(7x^2-x-8) ?
The asymptotes of f(x)=(x^2+2x+1)/(7x^2-x-8) is Vertical: x= 8/7 ,Horizontal: y= 1/7