What is the asymptotes of f(x)=(x^2-x-6)/(x^2-3x-4) ?

The asymptotes of f(x)=(x^2-x-6)/(x^2-3x-4) is Vertical: x=-1,x=4,Horizontal: y=1

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asymptotes of f(x)=(x^2-x-6)/(x^2-3x-4)

asymptotes

f (x) = \frac{x ^{2} - x - 6}{x ^{2} - 3 x - 4}

Vertical : x = - 1, x = 4, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - x - 6}{x ^{2} - 3 x - 4} : x = - 1, x = 4

Horizontal Asymptotes of

\frac{x ^{2} - x - 6}{x ^{2} - 3 x - 4} : y = 1

Slant Asymptotes of

\frac{x ^{2} - x - 6}{x ^{2} - 3 x - 4} :

None

Vertical : x = - 1, x = 4, Horizontal : y = 1

f (x) = \frac{x ^{2} + 3 x + 1}{x ^{2} + 5 x + 6}

f (x) = \frac{( x ^{2} )}{( x ^{2} - 1 )}

\frac{3 x ^{2} + 6}{x ^{2} - 2 x - 3}

f (x) = 5^{x - 6} + 5

f (x) = \frac{5 x - 20}{x ^{2} - 16}

What is the asymptotes of f(x)=(x^2-x-6)/(x^2-3x-4) ?
The asymptotes of f(x)=(x^2-x-6)/(x^2-3x-4) is Vertical: x=-1,x=4,Horizontal: y=1