What is the asymptotes of f(x)=(x^2+2x+1)/(x^2+3x-4) ?

The asymptotes of f(x)=(x^2+2x+1)/(x^2+3x-4) is Vertical: x=-4,x=1,Horizontal: y=1

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asymptotes of f(x)=(x^2+2x+1)/(x^2+3x-4)

asymptotes

f (x) = \frac{x ^{2} + 2 x + 1}{x ^{2} + 3 x - 4}

Vertical : x = - 4, x = 1, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x + 1}{x ^{2} + 3 x - 4} : x = - 4, x = 1

Horizontal Asymptotes of

\frac{x ^{2} + 2 x + 1}{x ^{2} + 3 x - 4} : y = 1

Slant Asymptotes of

\frac{x ^{2} + 2 x + 1}{x ^{2} + 3 x - 4} :

None

Vertical : x = - 4, x = 1, Horizontal : y = 1

f (x) = \frac{x ^{2} + 9}{x}

f (x) = \frac{2 x + 6}{x ^{2} - 9}

f (x) = \frac{x + 2}{x - 5}

f (x) = \frac{( x ^{2} )}{( x - 1 ) ^{2}}

f (x) = \frac{- x - x ^{2}}{( x + 1 ) ( x - 2 )}

What is the asymptotes of f(x)=(x^2+2x+1)/(x^2+3x-4) ?
The asymptotes of f(x)=(x^2+2x+1)/(x^2+3x-4) is Vertical: x=-4,x=1,Horizontal: y=1