What is the perpendicular y+1= 1/3 x,(2,-3) ?

The perpendicular y+1= 1/3 x,(2,-3) is y=-3x+3

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perpendicular y+1= 1/3 x,(2,-3)

perpendicular

y + 1 = \frac{1}{3} x, (2, - 3)

y = - 3 x + 3

Solution steps

Find the line

y = mx + b

perpendicular to

y + 1 = \frac{1}{3} x

that passes through

(2, - 3)

Find the slope of

y + 1 = \frac{1}{3} x : m = \frac{1}{3}

Compute the slope of the perpendicular line:

m_{p} = - 3

Find the line with slope m=

- 3

and passing through

(2, - 3) : y = - 3 x + 3

y = - 3 x + 3

f (x) = \frac{1}{ln ( x - 1 )}

f (x) = \frac{x - 2}{x ^{2} - 4}

y = \frac{1}{2} x + 5

2 x + 7

f (x) = \frac{x ^{2} - 2 x - 8}{x + 1}

What is the perpendicular y+1= 1/3 x,(2,-3) ?
The perpendicular y+1= 1/3 x,(2,-3) is y=-3x+3