What is the asymptotes of f(x)=(x^2-12)/(2x) ?

The asymptotes of f(x)=(x^2-12)/(2x) is Vertical: x=0,Slant: y= 1/2 x

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asymptotes of f(x)=(x^2-12)/(2x)

asymptotes

f (x) = \frac{x ^{2} - 12}{2 x}

Vertical : x = 0, Slant : y = \frac{1}{2} x

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 12}{2 x} : x = 0

Horizontal Asymptotes of

\frac{x ^{2} - 12}{2 x} :

None

Slant Asymptotes of

\frac{x ^{2} - 12}{2 x} : y = \frac{1}{2} x

Vertical : x = 0, Slant : y = \frac{1}{2} x

f (x) = \frac{2 x + 10}{x ^{2} + 4 x - 5}

f (x) = arctan (e^{- 5 x} + 1)

f (x) = \frac{x ^{2}}{( x - 4 ) ^{2}}

f (x) = \frac{8}{x ^{2} + 4}

f (x) = \frac{7 x}{x ^{2} - 4}

What is the asymptotes of f(x)=(x^2-12)/(2x) ?
The asymptotes of f(x)=(x^2-12)/(2x) is Vertical: x=0,Slant: y= 1/2 x