What is the asymptotes of h(x)=(x+1)/(x^2-16) ?

The asymptotes of h(x)=(x+1)/(x^2-16) is Vertical: x=-4,x=4,Horizontal: y=0

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asymptotes of h(x)=(x+1)/(x^2-16)

asymptotes

h (x) = \frac{x + 1}{x ^{2} - 16}

Vertical : x = - 4, x = 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x + 1}{x ^{2} - 16} : x = - 4, x = 4

Horizontal Asymptotes of

\frac{x + 1}{x ^{2} - 16} : y = 0

Slant Asymptotes of

\frac{x + 1}{x ^{2} - 16} :

None

Vertical : x = - 4, x = 4, Horizontal : y = 0

f (x) = \frac{x ^{2} + 16}{x ^{2} - 16}

f (x) = \frac{x}{- 3 x + 3}

f (x) = \frac{1}{25 - x ^{2}}

f (x) = \frac{x ^{2} + x - 6}{2 x ^{2} - 18}

f (x) = x^{2} - 9

What is the asymptotes of h(x)=(x+1)/(x^2-16) ?
The asymptotes of h(x)=(x+1)/(x^2-16) is Vertical: x=-4,x=4,Horizontal: y=0