What is the asymptotes of f(x)=arctan(e^{4x}+1) ?

The asymptotes of f(x)=arctan(e^{4x}+1) is Horizontal: y= pi/2 ,y= pi/4

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asymptotes of f(x)=arctan(e^{4x}+1)

asymptotes

f (x) = arctan (e^{4 x} + 1)

Horizontal : y = \frac{π}{2}, y = \frac{π}{4}

Solution steps

Vertical asymptotes of

arctan (e^{4 x} + 1) :

None

Horizontal Asymptotes of

arctan (e^{4 x} + 1) : y = \frac{π}{2}, y = \frac{π}{4}

Slant Asymptotes of

arctan (e^{4 x} + 1) :

None

Horizontal : y = \frac{π}{2}, y = \frac{π}{4}

4 y = 1

y = 2 sec (x) - 1

- 2 + ln (4 - 3 x)

\frac{4 x ^{2} - 16}{- 5 x + 10}

f (x) = \frac{( x ^{2} - 4 )}{x ^{2} + 4}

What is the asymptotes of f(x)=arctan(e^{4x}+1) ?
The asymptotes of f(x)=arctan(e^{4x}+1) is Horizontal: y= pi/2 ,y= pi/4