What is the asymptotes of f(x)=(3x^2-4)/(x+1) ?

The asymptotes of f(x)=(3x^2-4)/(x+1) is Vertical: x=-1,Slant: y=3x-3

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asymptotes of f(x)=(3x^2-4)/(x+1)

asymptotes

f (x) = \frac{3 x ^{2} - 4}{x + 1}

Vertical : x = - 1, Slant : y = 3 x - 3

Solution steps

Vertical asymptotes of

\frac{3 x ^{2} - 4}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{3 x ^{2} - 4}{x + 1} :

None

Slant Asymptotes of

\frac{3 x ^{2} - 4}{x + 1} : y = 3 x - 3

Vertical : x = - 1, Slant : y = 3 x - 3

f (x) = \frac{( x - 1 )}{( xx - 1 )}

f (x) = (x^{2} + 11) (4 - x^{2})

\frac{x}{x ( x - 2 )}

f (x) = \frac{1}{x ^{2} + 2}

- \frac{2}{x - 5}

What is the asymptotes of f(x)=(3x^2-4)/(x+1) ?
The asymptotes of f(x)=(3x^2-4)/(x+1) is Vertical: x=-1,Slant: y=3x-3