What is the asymptotes of f(x)= 1/((x+2)(x-5)) ?

The asymptotes of f(x)= 1/((x+2)(x-5)) is Vertical: x=-2,x=5,Horizontal: y=0

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asymptotes of f(x)= 1/((x+2)(x-5))

asymptotes

f (x) = \frac{1}{( x + 2 ) ( x - 5 )}

Vertical : x = - 2, x = 5, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{( x + 2 ) ( x - 5 )} : x = - 2, x = 5

Horizontal Asymptotes of

\frac{1}{( x + 2 ) ( x - 5 )} : y = 0

Slant Asymptotes of

\frac{1}{( x + 2 ) ( x - 5 )} :

None

Vertical : x = - 2, x = 5, Horizontal : y = 0

f (x) = x \cdot arccot (x)

f (x) = \frac{x + 1}{2 x - 4}

12 x^{\frac{2}{3}} - 8 x

f (x) = \frac{x + 6}{x ^{2} + x - 6}

ln (4 - ln (x))

What is the asymptotes of f(x)= 1/((x+2)(x-5)) ?
The asymptotes of f(x)= 1/((x+2)(x-5)) is Vertical: x=-2,x=5,Horizontal: y=0