What is the asymptotes of f(x)=(x-1)/((x+1)^2) ?

The asymptotes of f(x)=(x-1)/((x+1)^2) is Vertical: x=-1,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x-1)/((x+1)^2)

asymptotes

f (x) = \frac{x - 1}{( x + 1 ) ^{2}}

Vertical : x = - 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x - 1}{( x + 1 ) ^{2}} : x = - 1

Horizontal Asymptotes of

\frac{x - 1}{( x + 1 ) ^{2}} : y = 0

Slant Asymptotes of

\frac{x - 1}{( x + 1 ) ^{2}} :

None

Vertical : x = - 1, Horizontal : y = 0

f (x) = \frac{( x + 2 )}{( x ^{2} - 16 )}

\frac{- 3 x ^{2} + 3 x}{x + 1}

\frac{x ^{2} + 2 x - 3}{( x - 1 ) ( x ^{2} - 4 )}

f (x) = \frac{( sin ( x ) )}{x}

f (x) = \frac{- 4 x - 12}{3 x - 4}

What is the asymptotes of f(x)=(x-1)/((x+1)^2) ?
The asymptotes of f(x)=(x-1)/((x+1)^2) is Vertical: x=-1,Horizontal: y=0