What is the asymptotes of log_{2}(x+1) ?

The asymptotes of log_{2}(x+1) is Vertical: x=-1

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asymptotes of log_{2}(x+1)

asymptotes

lo g_{2} (x + 1)

Vertical : x = - 1

Solution steps

Vertical asymptotes of

lo g_{2} (x + 1) : x = - 1

Horizontal Asymptotes of

lo g_{2} (x + 1) :

None

Slant Asymptotes of

lo g_{2} (x + 1) :

None

Vertical : x = - 1

f (x) = \frac{1}{ln ( x )}

f (x) = \frac{x ^{2} - 6 x + 9}{( x - 1 ) ^{2}}

f (x) = \frac{( x + 1 )}{x ^{2}}

f (x) = \frac{- 5 x - 7}{x - 1}

f (x) = \frac{( 2 x ^{2} )}{( x ^{2} - 1 )}

What is the asymptotes of log_{2}(x+1) ?
The asymptotes of log_{2}(x+1) is Vertical: x=-1