What is the asymptotes of (x^2+4x)/(2x^2-7x) ?

The asymptotes of (x^2+4x)/(2x^2-7x) is Vertical: x= 7/2 ,Horizontal: y= 1/2

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asymptotes of (x^2+4x)/(2x^2-7x)

asymptotes

\frac{x ^{2} + 4 x}{2 x ^{2} - 7 x}

Vertical : x = \frac{7}{2}, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 4 x}{2 x ^{2} - 7 x} : x = \frac{7}{2}

Horizontal Asymptotes of

\frac{x ^{2} + 4 x}{2 x ^{2} - 7 x} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} + 4 x}{2 x ^{2} - 7 x} :

None

Vertical : x = \frac{7}{2}, Horizontal : y = \frac{1}{2}

f (x) = \frac{x ^{2} - 25}{x}

\frac{x + 2}{x ^{2} + 5 x + 6}

f (x) = \frac{25 x}{5 x ^{2} + 1}

f (x) = \frac{- 2 x - 2}{x + 3}

\frac{x + 2}{x ^{2} - 1}

What is the asymptotes of (x^2+4x)/(2x^2-7x) ?
The asymptotes of (x^2+4x)/(2x^2-7x) is Vertical: x= 7/2 ,Horizontal: y= 1/2