What is the asymptotes of f(x)=(x^2+9x+8)/(x^3-4x) ?

The asymptotes of f(x)=(x^2+9x+8)/(x^3-4x) is Vertical: x=-2,x=0,x=2,Horizontal: y=0

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asymptotes of f(x)=(x^2+9x+8)/(x^3-4x)

asymptotes

f (x) = \frac{x ^{2} + 9 x + 8}{x ^{3} - 4 x}

Vertical : x = - 2, x = 0, x = 2, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 9 x + 8}{x ^{3} - 4 x} : x = - 2, x = 0, x = 2

Horizontal Asymptotes of

\frac{x ^{2} + 9 x + 8}{x ^{3} - 4 x} : y = 0

Slant Asymptotes of

\frac{x ^{2} + 9 x + 8}{x ^{3} - 4 x} :

None

Vertical : x = - 2, x = 0, x = 2, Horizontal : y = 0

\frac{5 x ^{2}}{3 x ^{2} + 7 x}

x^{2} + 1 - x

\frac{3 x + 11}{4 x - 15}

\frac{x}{x ^{2} - 49}

f (x) = \frac{2 x ^{2} + 2}{x + 14 - 3 x ^{2}}

What is the asymptotes of f(x)=(x^2+9x+8)/(x^3-4x) ?
The asymptotes of f(x)=(x^2+9x+8)/(x^3-4x) is Vertical: x=-2,x=0,x=2,Horizontal: y=0