What is the critical x(x-2)^3 ?

The critical x(x-2)^3 is x= 1/2 ,x=2

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critical x(x-2)^3

critical points

x (x - 2)^{3}

x = \frac{1}{2}, x = 2

Solution steps

x (x - 2)^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{2}, x = 2

Identify critical points not in

f (x)

domain

Domain of

x (x - 2)^{3} : - \infty < x < \infty

All critical points are in domain

x = \frac{1}{2}, x = 2

f (x) = (x - 4)^{2}

- 4 x^{2} - 24 x - 28

f (x) = \frac{7}{x - 14}

y = m x + b

f (x) = \frac{x - 1}{x + 3}