What is the asymptotes of f(x)=sec(2x) ?

The asymptotes of f(x)=sec(2x) is Vertical: x=(3pi)/4+pin,x= pi/4+pin

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asymptotes of f(x)=sec(2x)

asymptotes

f (x) = sec (2 x)

Vertical : x = \frac{3 π}{4} + πn, x = \frac{π}{4} + πn

Solution steps

Vertical asymptotes of

sec (2 x) : x = \frac{3 π}{4} + πn, x = \frac{π}{4} + πn

Horizontal Asymptotes of

sec (2 x) :

None

Slant Asymptotes of

sec (2 x) :

None

Vertical : x = \frac{3 π}{4} + πn, x = \frac{π}{4} + πn

f (x) = x \cdot x + 6

f (x) = \frac{x ( x - 1 )}{( x - 1 ) ( x + 2 )}

f (x) = \frac{x + 1}{x ^{2} - 3 x + 2}

f (x) = \frac{5 x - 10}{x ^{2} - 2 x}

f (x) = 2 x + 5

What is the asymptotes of f(x)=sec(2x) ?
The asymptotes of f(x)=sec(2x) is Vertical: x=(3pi)/4+pin,x= pi/4+pin