What is the asymptotes of f(x)=(3x^3+2x^2-5)/(x^2-1) ?

The asymptotes of f(x)=(3x^3+2x^2-5)/(x^2-1) is Vertical: x=-1,Slant: y=3x+2

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asymptotes of f(x)=(3x^3+2x^2-5)/(x^2-1)

asymptotes

f (x) = \frac{3 x ^{3} + 2 x ^{2} - 5}{x ^{2} - 1}

Vertical : x = - 1, Slant : y = 3 x + 2

Solution steps

Vertical asymptotes of

\frac{3 x ^{3} + 2 x ^{2} - 5}{x ^{2} - 1} : x = - 1

Horizontal Asymptotes of

\frac{3 x ^{3} + 2 x ^{2} - 5}{x ^{2} - 1} :

None

Slant Asymptotes of

\frac{3 x ^{3} + 2 x ^{2} - 5}{x ^{2} - 1} : y = 3 x + 2

Vertical : x = - 1, Slant : y = 3 x + 2

f (x) = arctan (- e^{7 x} - 1)

f (x) = \frac{x ^{2} + 8 x - 20}{x + 3}

f (x) = \frac{- 5 x + 1}{2 x - 1}

f (x) = \frac{3 x + 4}{8 x - 32}

h (x) = (x^{2} + x) \cdot (x^{2} - 1)^{- 1}

What is the asymptotes of f(x)=(3x^3+2x^2-5)/(x^2-1) ?
The asymptotes of f(x)=(3x^3+2x^2-5)/(x^2-1) is Vertical: x=-1,Slant: y=3x+2