What is the asymptotes of f(x)=(sqrt(x^2-9))/(3x+1) ?

The asymptotes of f(x)=(sqrt(x^2-9))/(3x+1) is Horizontal: y= 1/3 ,y=-1/3

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asymptotes of f(x)=(sqrt(x^2-9))/(3x+1)

asymptotes

f (x) = \frac{x ^{2} - 9}{3 x + 1}

Horizontal : y = \frac{1}{3}, y = - \frac{1}{3}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 9}{3 x + 1} :

None

Horizontal Asymptotes of

\frac{x ^{2} - 9}{3 x + 1} : y = \frac{1}{3}, y = - \frac{1}{3}

Slant Asymptotes of

\frac{x ^{2} - 9}{3 x + 1} :

None

Horizontal : y = \frac{1}{3}, y = - \frac{1}{3}

f (x) = cos (x) - sin (x)

f (x) = arctan (e^{- 3 x} + 1)

f (x) = \frac{x}{2 - 3 x}

f (x) = \frac{2 x ^{2} - 4 x + 6}{x - 5}

f (x) = x + e^{- x} sin (x)

What is the asymptotes of f(x)=(sqrt(x^2-9))/(3x+1) ?
The asymptotes of f(x)=(sqrt(x^2-9))/(3x+1) is Horizontal: y= 1/3 ,y=-1/3