What is the asymptotes of f(x)=(x^2-6x-7)/(x+1) ?

The asymptotes of f(x)=(x^2-6x-7)/(x+1) is Slant: y=x-7

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asymptotes of f(x)=(x^2-6x-7)/(x+1)

asymptotes

f (x) = \frac{x ^{2} - 6 x - 7}{x + 1}

Slant : y = x - 7

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 6 x - 7}{x + 1} :

None

Horizontal Asymptotes of

\frac{x ^{2} - 6 x - 7}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} - 6 x - 7}{x + 1} : y = x - 7

Slant : y = x - 7

f (x) = \frac{3 x ^{2} - 2}{4 x ^{2} + 5}

f (x) = - (\frac{1}{2})^{x - 2} - 8

3 x^{4} + 4 x^{3}

f (x) = \frac{- 2 x + 1}{x - 3}

f (x) = \frac{x}{( x + 3 ) ^{2}}

What is the asymptotes of f(x)=(x^2-6x-7)/(x+1) ?
The asymptotes of f(x)=(x^2-6x-7)/(x+1) is Slant: y=x-7