What is the asymptotes of y=(x^2+1)/(x+1) ?

The asymptotes of y=(x^2+1)/(x+1) is Vertical: x=-1,Slant: y=x-1

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asymptotes of y=(x^2+1)/(x+1)

asymptotes

y = \frac{x ^{2} + 1}{x + 1}

Vertical : x = - 1, Slant : y = x - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 1}{x + 1} : y = x - 1

Vertical : x = - 1, Slant : y = x - 1

f (x) = \frac{x - 3}{x ^{2} - 3 x}

f (x) = \frac{4 x + 3}{x ^{2} - 4}

f (x) = \frac{1}{1 - x}

\frac{( x + 3 ) ( x - 3 )}{( x - 3 ) ( x + 2 )}

f (x) = \frac{2 x + 3}{4 x - 7}

What is the asymptotes of y=(x^2+1)/(x+1) ?
The asymptotes of y=(x^2+1)/(x+1) is Vertical: x=-1,Slant: y=x-1