What is the asymptotes of f(x)=(x^2-1)/(4x-5) ?

The asymptotes of f(x)=(x^2-1)/(4x-5) is Vertical: x= 5/4 ,Slant: y= 1/4 x+5/16

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asymptotes of f(x)=(x^2-1)/(4x-5)

asymptotes

f (x) = \frac{x ^{2} - 1}{4 x - 5}

Vertical : x = \frac{5}{4}, Slant : y = \frac{1}{4} x + \frac{5}{16}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 1}{4 x - 5} : x = \frac{5}{4}

Horizontal Asymptotes of

\frac{x ^{2} - 1}{4 x - 5} :

None

Slant Asymptotes of

\frac{x ^{2} - 1}{4 x - 5} : y = \frac{1}{4} x + \frac{5}{16}

Vertical : x = \frac{5}{4}, Slant : y = \frac{1}{4} x + \frac{5}{16}

\frac{x}{- 2 x + 5}

3 csc (\frac{3}{4}) θ

f (x) = \frac{x ^{2} + x}{x ^{3} + 2 x ^{2} - 8 x}

f (x) = 3 lo g_{3} (x)

\frac{( 2 - x ^{2} )}{x ^{2} + 9 x}

What is the asymptotes of f(x)=(x^2-1)/(4x-5) ?
The asymptotes of f(x)=(x^2-1)/(4x-5) is Vertical: x= 5/4 ,Slant: y= 1/4 x+5/16