What is the asymptotes of f(x)=(x^3-9)/(7x^5+6) ?

The asymptotes of f(x)=(x^3-9)/(7x^5+6) is Vertical: x=-\sqrt[5]{6/7},Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^3-9)/(7x^5+6)

asymptotes

f (x) = \frac{x ^{3} - 9}{7 x ^{5} + 6}

Solution steps

Vertical asymptotes of

Horizontal Asymptotes of

\frac{x ^{3} - 9}{7 x ^{5} + 6} : y = 0

Slant Asymptotes of

\frac{x ^{3} - 9}{7 x ^{5} + 6} :

None

f (x) = 2^{x - 5}

f (x) = \frac{x - 4}{x + 7}

\frac{x ^{3} - 9 x}{3 x ^{2} - 6 x - 9}

f (x) = \frac{1 - x ^{3}}{x ^{3} + 1}

15 x - 10

What is the asymptotes of f(x)=(x^3-9)/(7x^5+6) ?
The asymptotes of f(x)=(x^3-9)/(7x^5+6) is Vertical: x=-\sqrt[5]{6/7},Horizontal: y=0