What is the asymptotes of f(x)= 1/(x^2-3) ?

The asymptotes of f(x)= 1/(x^2-3) is Vertical: x=-sqrt(3),x=sqrt(3),Horizontal: y=0

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asymptotes of f(x)= 1/(x^2-3)

asymptotes

f (x) = \frac{1}{x ^{2} - 3}

Vertical : x = - 3, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{x ^{2} - 3} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{1}{x ^{2} - 3} : y = 0

Slant Asymptotes of

\frac{1}{x ^{2} - 3} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 0

\frac{x ^{2} + x - 12}{( x - 1 ) ( x + 4 )}

f (x) = (x - 2)^{2}

f (x) = \frac{3 + 4 ^{x}}{1 - 4 ^{x}}

y = \frac{( x + 1 ) ^{3}}{( x - 1 ) ^{2}}

f (x) = \frac{2 x - 1}{3 x + 4}

What is the asymptotes of f(x)= 1/(x^2-3) ?
The asymptotes of f(x)= 1/(x^2-3) is Vertical: x=-sqrt(3),x=sqrt(3),Horizontal: y=0