What is the inverse of sqrt(x^2+5x) ?

The inverse of sqrt(x^2+5x) is (-5+sqrt(25+4x^2))/2 ,(-5-sqrt(25+4x^2))/2

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inverse of sqrt(x^2+5x)

inverse

x^{2} + 5 x

\frac{- 5 + 25 + 4 x ^{2}}{2}, \frac{- 5 - 25 + 4 x ^{2}}{2}

Solution steps

y = x^{2} + 5 x

Replace

x

with

y

x = y^{2} + 5 y

Solve for

y, x = y^{2} + 5 y

\frac{- 5 + 25 + 4 x ^{2}}{2}, \frac{- 5 - 25 + 4 x ^{2}}{2}

x 9 - x^{2}

f (x) = 3 x - 18

2 x - 8

f (x) = 7 x - 3 y = 21

f (x) = \frac{5}{6} x - \frac{3}{4}

What is the inverse of sqrt(x^2+5x) ?
The inverse of sqrt(x^2+5x) is (-5+sqrt(25+4x^2))/2 ,(-5-sqrt(25+4x^2))/2