What is the asymptotes of 16y=2x^2+yx^2 ?

The asymptotes of 16y=2x^2+yx^2 is Vertical: x=-4,x=4,Horizontal: y=-2

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asymptotes of 16y=2x^2+yx^2

asymptotes

16 y = 2 x^{2} + y x^{2}

Vertical : x = - 4, x = 4, Horizontal : y = - 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2}}{16 - x ^{2}} : x = - 4, x = 4

Horizontal Asymptotes of

\frac{2 x ^{2}}{16 - x ^{2}} : y = - 2

Slant Asymptotes of

\frac{2 x ^{2}}{16 - x ^{2}} :

None

Vertical : x = - 4, x = 4, Horizontal : y = - 2

\frac{x}{1 - x ^{2}}

\frac{x + 3}{x - 6}

f (x) = ln (x - 4)

\frac{x ^{2} - 25}{4 x + 20}

- 2 - x

What is the asymptotes of 16y=2x^2+yx^2 ?
The asymptotes of 16y=2x^2+yx^2 is Vertical: x=-4,x=4,Horizontal: y=-2