What is the asymptotes of f(x)=(x-1)/(x^2-4x-5) ?

The asymptotes of f(x)=(x-1)/(x^2-4x-5) is Vertical: x=-1,x=5,Horizontal: y=0

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asymptotes of f(x)=(x-1)/(x^2-4x-5)

asymptotes

f (x) = \frac{x - 1}{x ^{2} - 4 x - 5}

Vertical : x = - 1, x = 5, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x - 1}{x ^{2} - 4 x - 5} : x = - 1, x = 5

Horizontal Asymptotes of

\frac{x - 1}{x ^{2} - 4 x - 5} : y = 0

Slant Asymptotes of

\frac{x - 1}{x ^{2} - 4 x - 5} :

None

Vertical : x = - 1, x = 5, Horizontal : y = 0

f (x) = \frac{x - 2}{x ^{2}}

f (x) = x^{2} e^{- 2 x}

f (x) = \frac{x}{ln ( x ^{4} )}

\frac{5 x + 5}{- x ^{2} - 2 x - 1}

f (x) = \frac{x ^{2} - 3 x}{x + 4}

What is the asymptotes of f(x)=(x-1)/(x^2-4x-5) ?
The asymptotes of f(x)=(x-1)/(x^2-4x-5) is Vertical: x=-1,x=5,Horizontal: y=0