What is the asymptotes of f(x)=(8x^2+1)/(2x^2+7x-4) ?

The asymptotes of f(x)=(8x^2+1)/(2x^2+7x-4) is Vertical: x=-4,x= 1/2 ,Horizontal: y=4

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asymptotes of f(x)=(8x^2+1)/(2x^2+7x-4)

asymptotes

f (x) = \frac{8 x ^{2} + 1}{2 x ^{2} + 7 x - 4}

Vertical : x = - 4, x = \frac{1}{2}, Horizontal : y = 4

Solution steps

Vertical asymptotes of

\frac{8 x ^{2} + 1}{2 x ^{2} + 7 x - 4} : x = - 4, x = \frac{1}{2}

Horizontal Asymptotes of

\frac{8 x ^{2} + 1}{2 x ^{2} + 7 x - 4} : y = 4

Slant Asymptotes of

\frac{8 x ^{2} + 1}{2 x ^{2} + 7 x - 4} :

None

Vertical : x = - 4, x = \frac{1}{2}, Horizontal : y = 4

f (x) = \frac{x ^{2} - 1}{x ^{2} + x}

f (x) = \frac{y ^{2} + 3}{5 - 2 y}

y = \frac{2 x - 3}{x - 3} - 2

\frac{10}{x + 3}

f (x) = \frac{x - 5}{x ^{2} - 5 x}

What is the asymptotes of f(x)=(8x^2+1)/(2x^2+7x-4) ?
The asymptotes of f(x)=(8x^2+1)/(2x^2+7x-4) is Vertical: x=-4,x= 1/2 ,Horizontal: y=4