What is the asymptotes of f(x)=(2x)/(sqrt(x^2-9)) ?

The asymptotes of f(x)=(2x)/(sqrt(x^2-9)) is Vertical: x=-3,x=3,Horizontal: y=2,y=-2

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asymptotes of f(x)=(2x)/(sqrt(x^2-9))

asymptotes

f (x) = \frac{2 x}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 2, y = - 2

Solution steps

Vertical asymptotes of

\frac{2 x}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{2 x}{x ^{2} - 9} : y = 2, y = - 2

Slant Asymptotes of

\frac{2 x}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 2, y = - 2

f (x) = \frac{( ( x + 1 ) ^{3} )}{( x - 1 ) ^{2}}

f (x) = lo g_{2} (x - 8)

- \frac{2 ( x ^{2} - 1 )}{x ^{2} - 4}

f (x) = 3 x^{2} - 2

\frac{4 x ^{2}}{2 x - 8}

What is the asymptotes of f(x)=(2x)/(sqrt(x^2-9)) ?
The asymptotes of f(x)=(2x)/(sqrt(x^2-9)) is Vertical: x=-3,x=3,Horizontal: y=2,y=-2