What is the asymptotes of y=(x^2-3x+2)/(9-4x^2) ?

The asymptotes of y=(x^2-3x+2)/(9-4x^2) is Vertical: x=-3/2 ,x= 3/2 ,Horizontal: y=-1/4

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asymptotes of y=(x^2-3x+2)/(9-4x^2)

asymptotes

y = \frac{x ^{2} - 3 x + 2}{9 - 4 x ^{2}}

Vertical : x = - \frac{3}{2}, x = \frac{3}{2}, Horizontal : y = - \frac{1}{4}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 3 x + 2}{9 - 4 x ^{2}} : x = - \frac{3}{2}, x = \frac{3}{2}

Horizontal Asymptotes of

\frac{x ^{2} - 3 x + 2}{9 - 4 x ^{2}} : y = - \frac{1}{4}

Slant Asymptotes of

\frac{x ^{2} - 3 x + 2}{9 - 4 x ^{2}} :

None

Vertical : x = - \frac{3}{2}, x = \frac{3}{2}, Horizontal : y = - \frac{1}{4}

f (x) = - 3 (\frac{1}{4})^{x + 2} + 5

f (x) = \frac{- 5 x + 7}{3 x + 7}

f (x) = e^{- x} - 2

f (x) = \frac{x + 1}{( x - 3 ) ( x + 2 )}

f (x) = \frac{3 x}{( x + 4 )}

What is the asymptotes of y=(x^2-3x+2)/(9-4x^2) ?
The asymptotes of y=(x^2-3x+2)/(9-4x^2) is Vertical: x=-3/2 ,x= 3/2 ,Horizontal: y=-1/4