What is the asymptotes of y=sec(4x) ?

The asymptotes of y=sec(4x) is Vertical: x=(3pi)/8+pi/2 n,x= pi/8+pi/2 n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of y=sec(4x)

asymptotes

y = sec (4 x)

Vertical : x = \frac{3 π}{8} + \frac{π}{2} n, x = \frac{π}{8} + \frac{π}{2} n

Solution steps

Vertical asymptotes of

sec (4 x) : x = \frac{3 π}{8} + \frac{π}{2} n, x = \frac{π}{8} + \frac{π}{2} n

Horizontal Asymptotes of

sec (4 x) :

None

Slant Asymptotes of

sec (4 x) :

None

Vertical : x = \frac{3 π}{8} + \frac{π}{2} n, x = \frac{π}{8} + \frac{π}{2} n

f (x) = 2^{x - 3} - 4

f (x) = \frac{2 x - 3}{3 x ^{2} - 3}

f (x) = \frac{( x + 1 ) ^{2}}{( x - 1 )}

f (x) = - 3 (3)^{x + 8} - 5

f (x) = \frac{x}{x ^{2} + 17}

What is the asymptotes of y=sec(4x) ?
The asymptotes of y=sec(4x) is Vertical: x=(3pi)/8+pi/2 n,x= pi/8+pi/2 n