What is the asymptotes of f(x)=(-3x^2+3x)/(x+1) ?

The asymptotes of f(x)=(-3x^2+3x)/(x+1) is Vertical: x=-1,Slant: y=-3x+6

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asymptotes of f(x)=(-3x^2+3x)/(x+1)

asymptotes

f (x) = \frac{- 3 x ^{2} + 3 x}{x + 1}

Vertical : x = - 1, Slant : y = - 3 x + 6

Solution steps

Vertical asymptotes of

\frac{- 3 x ^{2} + 3 x}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{- 3 x ^{2} + 3 x}{x + 1} :

None

Slant Asymptotes of

\frac{- 3 x ^{2} + 3 x}{x + 1} : y = - 3 x + 6

Vertical : x = - 1, Slant : y = - 3 x + 6

f (x) = \frac{3 - x}{2 - x}

\frac{x ^{2} - 1}{9 x ^{2} - 30 x}

9 - 9 x

\frac{12 t + 1}{( t + 1 ) ^{2}} - 1

f (x) = \frac{x - 4}{3}

What is the asymptotes of f(x)=(-3x^2+3x)/(x+1) ?
The asymptotes of f(x)=(-3x^2+3x)/(x+1) is Vertical: x=-1,Slant: y=-3x+6