What is the asymptotes of (16)/(x^2(x-4)) ?

The asymptotes of (16)/(x^2(x-4)) is Vertical: x=0,x=4,Horizontal: y=0

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asymptotes of (16)/(x^2(x-4))

asymptotes

\frac{16}{x ^{2} ( x - 4 )}

Vertical : x = 0, x = 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{16}{x ^{2} ( x - 4 )} : x = 0, x = 4

Horizontal Asymptotes of

\frac{16}{x ^{2} ( x - 4 )} : y = 0

Slant Asymptotes of

\frac{16}{x ^{2} ( x - 4 )} :

None

Vertical : x = 0, x = 4, Horizontal : y = 0

\frac{x ^{2} - 16}{x ^{2} - 9}

\frac{x ^{2} + x}{( x - 4 ) ( x - 2 )}

2 + ln (x)

\frac{( 2 x - 2 )}{x ^{2} + x} + 1

f (x) = \frac{2 x + 3}{x - 3}

What is the asymptotes of (16)/(x^2(x-4)) ?
The asymptotes of (16)/(x^2(x-4)) is Vertical: x=0,x=4,Horizontal: y=0