What is the asymptotes of f(x)=(2x^2+4)/(x^2-9) ?

The asymptotes of f(x)=(2x^2+4)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=2

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asymptotes of f(x)=(2x^2+4)/(x^2-9)

asymptotes

f (x) = \frac{2 x ^{2} + 4}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 4}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{2 x ^{2} + 4}{x ^{2} - 9} : y = 2

Slant Asymptotes of

\frac{2 x ^{2} + 4}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 2

\frac{x - 3}{x + 5}

f (x) = \frac{3 x + 1}{x ( 3 x - 1 )}

f (x) = \frac{x - 5}{x ^{2} - 9}

2 sec (\frac{π}{4} (x + 1))

f (x) = \frac{3 x - 5 x ^{3}}{2 x ^{3} + 2 x ^{2}}

What is the asymptotes of f(x)=(2x^2+4)/(x^2-9) ?
The asymptotes of f(x)=(2x^2+4)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=2