What is the domain of f(x)=((x^2+4))/(x^2+4x-5) ?

The domain of f(x)=((x^2+4))/(x^2+4x-5) is x 1

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domain of f(x)=((x^2+4))/(x^2+4x-5)

domain

f (x) = \frac{( x ^{2} + 4 )}{x ^{2} + 4 x - 5}

x < - 5 or - 5 < x < 1 or x > 1

Interval Notation

(- \infty, - 5) \cup (- 5, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 5

The function domain

x < - 5 or - 5 < x < 1 or x > 1

x + 6

(2, 2), (1, 1)

f (x) = 6 csc (\frac{1}{2} π x - \frac{1}{6} π)

f (x) = \frac{x ^{2} - x - 6}{x ^{2} - 7 x + 10}

f (x) = 5 x^{2} + 10 x + 6

What is the domain of f(x)=((x^2+4))/(x^2+4x-5) ?
The domain of f(x)=((x^2+4))/(x^2+4x-5) is x<-5\lor-5<x<1\lor x>1