What is the asymptotes of f(x)= x/((2x+1)^2) ?

The asymptotes of f(x)= x/((2x+1)^2) is Vertical: x=-1/2 ,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)= x/((2x+1)^2)

asymptotes

f (x) = \frac{x}{( 2 x + 1 ) ^{2}}

Vertical : x = - \frac{1}{2}, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x}{( 2 x + 1 ) ^{2}} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{x}{( 2 x + 1 ) ^{2}} : y = 0

Slant Asymptotes of

\frac{x}{( 2 x + 1 ) ^{2}} :

None

Vertical : x = - \frac{1}{2}, Horizontal : y = 0

f (x) = \frac{8}{x - 4}

f (x) = \frac{( 3 x + 6 )}{( 10 x - 20 )}

y = 2^{x - 5}

f (x) = \frac{4 x - 5}{2 x ^{2} - 8}

\frac{7 x ^{2} + 5 x - 2}{2 x ^{2} - 18}

What is the asymptotes of f(x)= x/((2x+1)^2) ?
The asymptotes of f(x)= x/((2x+1)^2) is Vertical: x=-1/2 ,Horizontal: y=0