What is the asymptotes of f(x)=(x^2+4)/(2x) ?

The asymptotes of f(x)=(x^2+4)/(2x) is Vertical: x=0,Slant: y= 1/2 x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2+4)/(2x)

asymptotes

f (x) = \frac{x ^{2} + 4}{2 x}

Vertical : x = 0, Slant : y = \frac{1}{2} x

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 4}{2 x} : x = 0

Horizontal Asymptotes of

\frac{x ^{2} + 4}{2 x} :

None

Slant Asymptotes of

\frac{x ^{2} + 4}{2 x} : y = \frac{1}{2} x

Vertical : x = 0, Slant : y = \frac{1}{2} x

f (x) = \frac{15 x ^{2}}{3 x ^{2} + 1}

f (x) = x^{4} - x^{3} + x^{2} - x

\frac{5 x}{x ^{2} - 25}

f (x) = \frac{x ^{2} + 2 x - 15}{x ^{3} + 1}

f (x) = \frac{x ^{2} + 3 x + 2}{x ^{2} - 1}

What is the asymptotes of f(x)=(x^2+4)/(2x) ?
The asymptotes of f(x)=(x^2+4)/(2x) is Vertical: x=0,Slant: y= 1/2 x