What is the asymptotes of f(x)=(x^2-6x+8)/(2x-4) ?

The asymptotes of f(x)=(x^2-6x+8)/(2x-4) is Slant: y= 1/2 x-2

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asymptotes of f(x)=(x^2-6x+8)/(2x-4)

asymptotes

f (x) = \frac{x ^{2} - 6 x + 8}{2 x - 4}

Slant : y = \frac{1}{2} x - 2

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 6 x + 8}{2 x - 4} :

None

Horizontal Asymptotes of

\frac{x ^{2} - 6 x + 8}{2 x - 4} :

None

Slant Asymptotes of

\frac{x ^{2} - 6 x + 8}{2 x - 4} : y = \frac{1}{2} x - 2

Slant : y = \frac{1}{2} x - 2

f (x) = \frac{( x ^{2} + x - 6 )}{( x - 3 )}

f (x) = \frac{- 3 x + 12}{x ^{2} - 4 x}

f (x) = (x^{2} - 1)^{2}

f (x) = \frac{5 x ^{2} - 2 x}{e ^{x}}

f (x) = 3 x^{5} + 5 x^{3}

What is the asymptotes of f(x)=(x^2-6x+8)/(2x-4) ?
The asymptotes of f(x)=(x^2-6x+8)/(2x-4) is Slant: y= 1/2 x-2