What is the asymptotes of f(x)=((x^2-4))/((x+1)) ?

The asymptotes of f(x)=((x^2-4))/((x+1)) is Vertical: x=-1,Slant: y=x-1

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asymptotes of f(x)=((x^2-4))/((x+1))

asymptotes

f (x) = \frac{( x ^{2} - 4 )}{( x + 1 )}

Vertical : x = - 1, Slant : y = x - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} - 4}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} - 4}{x + 1} : y = x - 1

Vertical : x = - 1, Slant : y = x - 1

+ 2 sin (\frac{1}{4} x)

y = \frac{x - 2}{x ^{2} - 4}

\frac{( x - 1 )}{x ^{2} - 1}

f (x) = e^{x - 1} + 4

f (x) = lo g_{3} (x - 2) - 3

What is the asymptotes of f(x)=((x^2-4))/((x+1)) ?
The asymptotes of f(x)=((x^2-4))/((x+1)) is Vertical: x=-1,Slant: y=x-1