What is the asymptotes of f(x)=(x^2+3x-4)/(x^2-16) ?

The asymptotes of f(x)=(x^2+3x-4)/(x^2-16) is Vertical: x=4,Horizontal: y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2+3x-4)/(x^2-16)

asymptotes

f (x) = \frac{x ^{2} + 3 x - 4}{x ^{2} - 16}

Vertical : x = 4, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 3 x - 4}{x ^{2} - 16} : x = 4

Horizontal Asymptotes of

\frac{x ^{2} + 3 x - 4}{x ^{2} - 16} : y = 1

Slant Asymptotes of

\frac{x ^{2} + 3 x - 4}{x ^{2} - 16} :

None

Vertical : x = 4, Horizontal : y = 1

f (x) = \frac{( x ^{2} + 2 x + 1 )}{2 x + 2}

\frac{x ^{2} - x}{x + 1}

f (x) = arctan (- e^{2 x} + 1)

\frac{( 6 x ^{2} + 3 x + 1 )}{( 3 x ^{2} + 4 )}

f (x) = \frac{2 x ^{2} - 18}{x ^{2} - 16}

What is the asymptotes of f(x)=(x^2+3x-4)/(x^2-16) ?
The asymptotes of f(x)=(x^2+3x-4)/(x^2-16) is Vertical: x=4,Horizontal: y=1