What is the asymptotes of f(x)=(3x^2+x-4)/(2x^2-7x) ?

The asymptotes of f(x)=(3x^2+x-4)/(2x^2-7x) is Vertical: x=0,x= 7/2 ,Horizontal: y= 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(3x^2+x-4)/(2x^2-7x)

asymptotes

f (x) = \frac{3 x ^{2} + x - 4}{2 x ^{2} - 7 x}

Vertical : x = 0, x = \frac{7}{2}, Horizontal : y = \frac{3}{2}

Solution steps

Vertical asymptotes of

\frac{3 x ^{2} + x - 4}{2 x ^{2} - 7 x} : x = 0, x = \frac{7}{2}

Horizontal Asymptotes of

\frac{3 x ^{2} + x - 4}{2 x ^{2} - 7 x} : y = \frac{3}{2}

Slant Asymptotes of

\frac{3 x ^{2} + x - 4}{2 x ^{2} - 7 x} :

None

Vertical : x = 0, x = \frac{7}{2}, Horizontal : y = \frac{3}{2}

f (x) = \frac{2 x + 1}{2 x - 4}

cos (3 x)

f (x) = \frac{2 x + 5}{x - 2}

f (x) = \frac{- 4 x ^{2}}{x + 6}

f (x) = \frac{x ^{2} - 1}{( x - 1 ) ^{2}}

What is the asymptotes of f(x)=(3x^2+x-4)/(2x^2-7x) ?
The asymptotes of f(x)=(3x^2+x-4)/(2x^2-7x) is Vertical: x=0,x= 7/2 ,Horizontal: y= 3/2