What is the asymptotes of f(x)=(2x^2+1)/(4x-x^2) ?

The asymptotes of f(x)=(2x^2+1)/(4x-x^2) is Vertical: x=0,x=4,Horizontal: y=-2

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asymptotes of f(x)=(2x^2+1)/(4x-x^2)

asymptotes

f (x) = \frac{2 x ^{2} + 1}{4 x - x ^{2}}

Vertical : x = 0, x = 4, Horizontal : y = - 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 1}{4 x - x ^{2}} : x = 0, x = 4

Horizontal Asymptotes of

\frac{2 x ^{2} + 1}{4 x - x ^{2}} : y = - 2

Slant Asymptotes of

\frac{2 x ^{2} + 1}{4 x - x ^{2}} :

None

Vertical : x = 0, x = 4, Horizontal : y = - 2

f (x) = \frac{2}{4 x ^{2} + 10 x - 6}

f (x) = \frac{1}{x + 17}

f (x) = \frac{2}{x} + \frac{x}{2}

f (x) = 2^{x - 4}

x^{2} - 4 x + 5

What is the asymptotes of f(x)=(2x^2+1)/(4x-x^2) ?
The asymptotes of f(x)=(2x^2+1)/(4x-x^2) is Vertical: x=0,x=4,Horizontal: y=-2