What is the asymptotes of f(x)=(x^2+5)/(x+1) ?

The asymptotes of f(x)=(x^2+5)/(x+1) is Vertical: x=-1,Slant: y=x-1

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asymptotes of f(x)=(x^2+5)/(x+1)

asymptotes

f (x) = \frac{x ^{2} + 5}{x + 1}

Vertical : x = - 1, Slant : y = x - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 5}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 5}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 5}{x + 1} : y = x - 1

Vertical : x = - 1, Slant : y = x - 1

\frac{1}{1 - x ^{2}}

- 3^{3 - 2 x} + 2

x^{2} - 1

f (x) = 0. 3^{x - 2} - 4

f (x) = \frac{7 + 9 x ^{2}}{1 - 2 x}

What is the asymptotes of f(x)=(x^2+5)/(x+1) ?
The asymptotes of f(x)=(x^2+5)/(x+1) is Vertical: x=-1,Slant: y=x-1