What is the asymptotes of f(x)=(8x^2-10x-1)/(2x-3) ?

The asymptotes of f(x)=(8x^2-10x-1)/(2x-3) is Vertical: x= 3/2 ,Slant: y=4x+1

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asymptotes of f(x)=(8x^2-10x-1)/(2x-3)

asymptotes

f (x) = \frac{8 x ^{2} - 10 x - 1}{2 x - 3}

Vertical : x = \frac{3}{2}, Slant : y = 4 x + 1

Solution steps

Vertical asymptotes of

\frac{8 x ^{2} - 10 x - 1}{2 x - 3} : x = \frac{3}{2}

Horizontal Asymptotes of

\frac{8 x ^{2} - 10 x - 1}{2 x - 3} :

None

Slant Asymptotes of

\frac{8 x ^{2} - 10 x - 1}{2 x - 3} : y = 4 x + 1

Vertical : x = \frac{3}{2}, Slant : y = 4 x + 1

\frac{x ^{2} + 2 x - 3}{x + 1}

\frac{1}{2 x + 3}

f (x) = \frac{7 x}{x - 3}

f (x) = \frac{7 x}{x - 2}

f (x) = arctan (- e^{6 x} - 1)

What is the asymptotes of f(x)=(8x^2-10x-1)/(2x-3) ?
The asymptotes of f(x)=(8x^2-10x-1)/(2x-3) is Vertical: x= 3/2 ,Slant: y=4x+1