What is the asymptotes of f(x)=(x^2-5x+6)/(x^2-9) ?

The asymptotes of f(x)=(x^2-5x+6)/(x^2-9) is Vertical: x=-3,Horizontal: y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2-5x+6)/(x^2-9)

asymptotes

f (x) = \frac{x ^{2} - 5 x + 6}{x ^{2} - 9}

Vertical : x = - 3, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 5 x + 6}{x ^{2} - 9} : x = - 3

Horizontal Asymptotes of

\frac{x ^{2} - 5 x + 6}{x ^{2} - 9} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 5 x + 6}{x ^{2} - 9} :

None

Vertical : x = - 3, Horizontal : y = 1

f (x) = \frac{x - 2}{x + 4}

\frac{2 x + 6}{x + 4}

f (x) = \frac{x ^{2} - 1}{( x + 1 ) ( x - 1 )}

f (x) = sec (π x) - 3

f (x) = \frac{1}{x + 7} + 3

What is the asymptotes of f(x)=(x^2-5x+6)/(x^2-9) ?
The asymptotes of f(x)=(x^2-5x+6)/(x^2-9) is Vertical: x=-3,Horizontal: y=1