What is the asymptotes of f(x)=(3x^2+10x-48)/(x-5) ?

The asymptotes of f(x)=(3x^2+10x-48)/(x-5) is Vertical: x=5,Slant: y=3x+25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(3x^2+10x-48)/(x-5)

asymptotes

f (x) = \frac{3 x ^{2} + 10 x - 48}{x - 5}

Vertical : x = 5, Slant : y = 3 x + 25

Solution steps

Vertical asymptotes of

\frac{3 x ^{2} + 10 x - 48}{x - 5} : x = 5

Horizontal Asymptotes of

\frac{3 x ^{2} + 10 x - 48}{x - 5} :

None

Slant Asymptotes of

\frac{3 x ^{2} + 10 x - 48}{x - 5} : y = 3 x + 25

Vertical : x = 5, Slant : y = 3 x + 25

f (x) = \frac{18 - 2 x ^{2}}{x ^{2} - 9}

f (x) = \frac{2 x}{x - 6}

e^{\frac{1}{x - 2}}

f (x) = \frac{396}{x + 33}

f (x) = \frac{x ^{2} + 2}{x}

What is the asymptotes of f(x)=(3x^2+10x-48)/(x-5) ?
The asymptotes of f(x)=(3x^2+10x-48)/(x-5) is Vertical: x=5,Slant: y=3x+25