What is the asymptotes of f(x)=((5+2^x))/((1-2^x)) ?

The asymptotes of f(x)=((5+2^x))/((1-2^x)) is Vertical: x=0,Horizontal: y=-1,y=5

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asymptotes of f(x)=((5+2^x))/((1-2^x))

asymptotes

f (x) = \frac{( 5 + 2 ^{x} )}{( 1 - 2 ^{x} )}

Vertical : x = 0, Horizontal : y = - 1, y = 5

Solution steps

Vertical asymptotes of

\frac{5 + 2 ^{x}}{1 - 2 ^{x}} : x = 0

Horizontal Asymptotes of

\frac{5 + 2 ^{x}}{1 - 2 ^{x}} : y = - 1, y = 5

Slant Asymptotes of

\frac{5 + 2 ^{x}}{1 - 2 ^{x}} :

None

Vertical : x = 0, Horizontal : y = - 1, y = 5

\frac{x ^{2}}{x - 4}

(\frac{1}{3})^{x} + 1

f (x) = \frac{2 x + 1}{x ^{2} ( x + 1 ) ^{2}}

f (x) = - 7, x = - 2

\frac{3 x - x ^{2}}{2 x - 2}

What is the asymptotes of f(x)=((5+2^x))/((1-2^x)) ?
The asymptotes of f(x)=((5+2^x))/((1-2^x)) is Vertical: x=0,Horizontal: y=-1,y=5